how to get node level in c

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Ali Sheikh Taheri 470 posts 1647 karma points c-trib

Aug 04, 2010 @ 16:41

0

how to get node level in c#?

is there any way that I can get the level of a node in c#?

basically I want to get the parent node of a node that has the level 2.

here is the site structure:

-site

-----news

------------2010

----------------08

---------------------- article 1

----- FAQ

---------- faq items

I know I can use this :

Node currentNodeRoot = Node.GetCurrent().Parent.Parent.Parent;

but I want the above code to be dynamic and as you can see FAQ the above code is not working with FAQ because of the structure.

Any thought ?

Cheers

Ali

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Sebastiaan Janssen 4899 posts 14655 karma points MVP admin hq

Aug 04, 2010 @ 16:53

0

Have a look at this topic, it should be helpful.

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Ali Sheikh Taheri 470 posts 1647 karma points c-trib

Aug 04, 2010 @ 16:57

0

Thanks for your post. - your 1000th post:)

What class shall I extend to be able to do that?

Cheers

Ali

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Matt Brailsford 2958 posts 15629 karma points MVP 7x c-trib

Aug 04, 2010 @ 16:59

1

Hey Ali,

I'd also check here, includes code samples

http://our.umbraco.org/forum/developers/api-questions/11190-Level-property-from-Node

Matt

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Ali Sheikh Taheri 470 posts 1647 karma points c-trib

Aug 04, 2010 @ 17:28
0
thanks matt,

I am going to use this wicked code:
```
umbraco.presentation.nodeFactory.Node.GetCurrent().Path.Split(',').Length
```
Cheers Matt

Ali
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