using xpathnodeiterator to generate xml in codebehind

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Fengelz 106 posts 221 karma points

Aug 28, 2009 @ 15:10
0

Using XPathNodeIterator to generate xml in Codebehind
I'm pretty new to this whole Xpath Xquery thingy. so please forgive this newbie question.

I have a function in a class and I wish to get a specific node from the content by fx and attribute.

My question is: how do you get the xml output from a nodeiterator?

I have a function:
```
private string GetXmlString()
{
 XPathNodeIterator n = umbraco.library.GetXmlNodeByXPath("//node [@id = 1079]");
    return n.Current.InnerXml;
}
```
this always generates the full site document.

How does one go about and get xml in this manner?

best regards Sune Fengel
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Chris Koiak 700 posts 2626 karma points

Aug 29, 2009 @ 09:21

Hi Fenglez

Try

private string GetXmlString()
{
        XPathNodeIterator n = umbraco.library.GetXmlNodeByXPath("//node [@id = 1079]");
        n.MoveNext();
        return n.Current.InnerXml;
}

The XPathNodeIterator may still be positioned at the root node.

Cheers,

Chris

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Fengelz 106 posts 221 karma points

Aug 31, 2009 @ 16:24

0

sweet :)

thanks for the pointer, works like a charm.

- Sune

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Using XPathNodeIterator to generate xml in Codebehind