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  • Chris Heijnen 6 posts 26 karma points
    Mar 10, 2013 @ 09:46
    Chris Heijnen
    0

    Get single random node from MNTP

    Hi Guys,

    The title actually explains my issue but what i want is to display 1 Random node from multiple nodes i have selected with the MNTP. 

    With this code i'm getting all the node (id's) and returning the property's in it, so that part works fine. Just want to display 1 randomly.

    @{

    var topNode = Model.AncestorOrSelf(1);

    foreach (var reference in topNode.referencesPicker)
    {

        var referenceNode = Model.NodeById(reference.InnerText);

        <h3>@referenceNode.referenceName</h3>
        <span>@referenceNode.referenceOneliner</span>
        @referenceNode.referenceText

    }

 }

    Chris

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  • gary 385 posts 915 karma points
    Mar 10, 2013 @ 10:26
    gary
    0

    Hi Chris

    foreach(var reference in topNode.referencesPicker).Random(1)

    should work for you.

    G

     

     

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  • Chris Heijnen 6 posts 26 karma points
    Mar 10, 2013 @ 10:33
    Chris Heijnen
    0

    Hi Gary,

    I think that's not going to work. Getting syntax error on that. If i write it down this way:

     foreach (var reference in (topNode.referencesPicker).Random(1))

    I get this error: 'umbraco.MacroEngines.DynamicXml' does not contain a definition for 'Random' 

    any suggestions?

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  • gary 385 posts 915 karma points
    Mar 10, 2013 @ 10:40
    gary
    0

    Ah

    The MNTP throws that one!

    Found this answer here which you should be able to adapt if it doesn't work directly - it explains how it works.

    http://our.umbraco.org/forum/developers/razor/22237-Random-uComponents-Multi-Node-Tree-Picker

    Hope it helps G

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  • Chris Heijnen 6 posts 26 karma points
    Mar 10, 2013 @ 10:52
    Chris Heijnen
    0

    Hi Gary,

    I already looked at that solution but i couldn't figure it out. Now with a fresh look i made it work! 

    This is the working code btw:

    @{
var topNode = Model.AncestorOrSelf(1);

    var nodes = new DynamicNodeList();

    foreach(var referenceItem in topNode.referencesPicker){
        var n = new DynamicNode(referenceItem.InnerText);
        nodes.Add(n);
    }

    foreach (dynamic reference in nodes.Random(1))
    {

    @reference.referenceName

            @reference.referenceOneliner
        @reference.referenceText

    }
}

    Thanks!

     

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