<xsl:if test="$url != ''">

instead of 

<xsl:if test="$url &gt; 0">

Hi

That was my thinking, but the link is not displayed?  

Thanks

Eddie

Hi

Just tried this, which does produce a link.  Regardless of whether a folder has been selected?

  <xsl:template match="/">
    <xsl:for-each select="$currentPage/descendant::node ">
      <xsl:if test="./data [@alias = 'factSheetsArchive'] != ' '">
        <small>
          <a href="{umbraco.library:NiceUrl(@id)}" class="new-window" title="Fund Archived Documents">Archived Documents</a>
        </small>
      </xsl:if>     
    </xsl:for-each>
  </xsl:template>

Also tried and removed the currentPage

<xsl:for-each select="$currentPage/descendant::node ">

but this resulted in no link?

Thanks

Eddie

Hi Eddie,

The error in the first attempt is that your're saying "select the descendant node that has a factSheetArchive property" - so you're actually selecting the 'Archive' node instead of the property. You can do a couple of things to correct it:

1. If the Archive node is a child of Funds, do this:

<xsl:variable name="url" select="node[@nodeName = 'Archive']/data[@alias = 'factSheetsArchive']" />

2. You could just add the property to the XPath to actually select it:

<xsl:variable name="url" select="descendant::node[data[@alias = 'factSheetsArchive']/data[@alias = 'factSheetsArchive']" />

/Chriztian

Hi again,

Just realized that that won't even work because you're inside the root template, so the context is wrong - you need to add $currentPage to the mix:

xsl:variable name="url" select="$currentPage/node[@nodeName = 'Archive']/data[@alias = 'factSheetsArchive']" />

/Chriztian

Hi /Chriztain

Thanks for this, still no joy.

The archive page has an id of 1275, so as a test I've updated the xslt to:

  <xsl:param name="currentPage"/>
  <xsl:template match="/">
    <xsl:variable name="url" select="node[@id = '1275']/data[@alias = 'factSheetsArchive']" />
    <xsl:if test="$url != ''">
      <small>
        <a href="{umbraco.library:NiceUrl($url)}" class="new-window" title="Fund Archived Documents">Archived Documents</a>
      </small>
    </xsl:if>
  </xsl:template>

But again, still no link.

Is the if test conditon correct?  If I remove this I get an error, from the following:

{umbraco.library:NiceUrl($url)}

Thanks

Eddie

Sorry, just saw your last post, so added to the above test, but still the same?

  <xsl:variable name="url" select="$currentPage/node[@id = '1275']/data[@alias = 'factSheetsArchive']" />

Hi Eddie,

That'll only work when the current page is the parent of the page with id="1275" - you can use the GetXmlNodeById() function to grab that node, regardless of your current position:

<xsl:variable name="url" select="umbraco.library:GetXmlNodeById(1275)/data[@alias = 'factSheetsArchive']" />

/Chriztian 

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