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  • Max Öhman 42 posts 71 karma points
    Dec 22, 2010 @ 10:32
    Max Öhman
    0

    Get position of the third-last node, 4.5

    Hi everybody!
    I'm trying to figure out a good way of getting the position of the third-last node. I'm using a for-each to create a navigation menu and I really want change attributes of the last, second-last and third-last node.

    I've made some efforts using preceding-sibling:: but I'm still a bit new to all this and can't manage to completing my code. 

    Thank you for taking a look at my problem and hopefully you can help me out!

    Cheers /Max

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  • Chriztian Steinmeier 2726 posts 8320 karma points MVP 4x admin c-trib
    Dec 22, 2010 @ 10:45
    Chriztian Steinmeier
    2

    Hi Max,

    Here's one way to get it - depends a little on what you're trying to achieve, but this will work inside the for-each:

    <xsl:if test="position() = last() - 2">
    <!-- do stuff -->
</xsl:if>

    /Chriztian

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  • Chris Koiak 700 posts 2626 karma points
    Dec 22, 2010 @ 10:48
    Chris Koiak
    0

    Hi Max,

    You can use the XLST functions count() and position() to achieve this.

    <xsl:for-each select="$yourNodes">
      <xsl:if test="position() = (count($yourNodes)-1)">
        2nd last node
      </xsl:if>
    <xsl:for-each>
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  • Max Öhman 42 posts 71 karma points
    Dec 22, 2010 @ 16:17
    Max Öhman
    0

    Thank you so much, both of you!

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