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Hi there...
I'm creating this navigation in xslt, and I'm using an unordered list (ul>li) to do this.
<xsl:if test="count(child::*) > 0"> <ul> <xsl:for-each select="$startItem/*[@isDoc and name() !='IntranetFolder']"> <xsl:variable name="leftnav" select="current()/hideFromLeftMenu"/> <xsl:if test="($leftnav != '1')"> <li>
the above works , as long as the "ul" has children that have the hideFromLeftMenu set to false ('0').
I was wondering, if it is possible to check for the hideFromLeftMenu before the xsl:for-each loop ? Maybe check for it in the count?
Best regardsMartin
Hi Martin,
Rule of thumb is to test with the same conditions - but you can use an intermediate variable to improve readability (and remove duplication), e.g.:
<xsl:variable name="nodes" select="$startItem/*[@isDoc][not(self::IntranetFolder)][not(hideFromLeftMenu = 1)]" /> <xsl:if test="$nodes"> <ul> <xsl:for-each select="$nodes"> <li> <!-- etc... --> </li> </xsl:for-each> </ul> </xsl:if>
/Chriztian
I'm not sure .... I'm only interested in printing the <ul> if count(children) > 0 and at least one of the children has hideFromLeftMenu = 0 :)
Would the above solution work for this scenario?
It seems like your solution worked :D
Thanks alot
Best regardsMartin.
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XSLT Navigation
Hi there...
I'm creating this navigation in xslt, and I'm using an unordered list (ul>li) to do this.
<xsl:if test="count(child::*) > 0">
<ul>
<xsl:for-each select="$startItem/*[@isDoc and name() !='IntranetFolder']">
<xsl:variable name="leftnav" select="current()/hideFromLeftMenu"/>
<xsl:if test="($leftnav != '1')">
<li>
the above works , as long as the "ul" has children that have the hideFromLeftMenu set to false ('0').
I was wondering, if it is possible to check for the hideFromLeftMenu before the xsl:for-each loop ? Maybe check for it in the count?
Best regards
Martin
Hi Martin,
Rule of thumb is to test with the same conditions - but you can use an intermediate variable to improve readability (and remove duplication), e.g.:
<xsl:variable name="nodes" select="$startItem/*[@isDoc][not(self::IntranetFolder)][not(hideFromLeftMenu = 1)]" /> <xsl:if test="$nodes"> <ul> <xsl:for-each select="$nodes"> <li> <!-- etc... --> </li> </xsl:for-each> </ul> </xsl:if>/Chriztian
I'm not sure .... I'm only interested in printing the <ul> if count(children) > 0 and at least one of the children has hideFromLeftMenu = 0 :)
Would the above solution work for this scenario?
It seems like your solution worked :D
Thanks alot
Best regards
Martin.
is working on a reply...
This forum is in read-only mode while we transition to the new forum.
You can continue this topic on the new forum by tapping the "Continue discussion" link below.