Hi im using this xslt to pick som products and show their data. 

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#xA0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">
  <xsl:output method="xml" omit-xml-declaration="yes"/>

  <xsl:param name="currentPage"/>

  <xsl:template match="/">
    <xsl:variable name="preNodes">
          <xsl:variable name="relatedContent" select="$currentPage/productPicker" />
          <xsl:variable name="nodeIds" select="umbraco.library:Split($relatedContent, ',')" />
      <xsl:for-each select="$nodeIds/value">
            <xsl:copy-of select="umbraco.library:GetXmlNodeById(.)"/>
          </xsl:for-each>
    </xsl:variable>
  
  <xsl:variable name="nodes" select="msxml:node-set($preNodes)/*[@isDoc]" />
  <xsl:if test="count($nodes) > 0">

  <ul class="productList">
    <xsl:for-each select="$nodes">
  <li class="two left marginTop10px">
  

   <a href="{umbraco.library:NiceUrl(@id)}">
     <xsl:value-of select="$currentPage/preceding::node/@nodeName"/>
    </a>   
    
  </li>
            
</xsl:for-each>
    </ul>
</xsl:if>
  </xsl:template>

</xsl:stylesheet>

This works fine but in the url I need to get the parent url instead of the current. 

  <xsl:value-of select="$currentPage/preceding::node/@nodeName"/>

I tried this but it didn't work. Any ideas how to get the parent for the selected page and not the selected one?

Thanks / Niklas