Hi Biagio,

If $currentPage is "NodeA" and "Home" is the alias of the Document Type for the hidden node, you can very easily access the children of Home by doing this:

<xsl:for-each select="$currentPage/Home/*[@isDoc]">
    <p><xsl:value-of select="@nodeName" /></p>
</xsl:for-each>

The fact that the node is hidden, is just a convention that if you use a property with the name umbracoNaviHide, the default XSLT "templates" (accessible in the Create XSLT file dialog) will skip nodes that have that property set. You can only truly hide a node from the XML by unpublishing it.

/Chriztian

I try, but don't works...My script is:

<xsl:value-of select="$currentPage/@nodeName"/>  --> this return "it" value
              <ul class="tabbed">

                <xsl:for-each select="$currentPage/Home/*[@isDoc]">
                   
            <li>
              <xsl:if test="@id = current()/@id">
                <xsl:attribute name="class">current-tab</xsl:attribute>
              </xsl:if>
              <a href="{umbraco.library:NiceUrl(@id)}">
                  <xsl:attribute name="id">nav-<xsl:value-of select="./umbracoUrlName"/></xsl:attribute>
                <xsl:value-of select="@nodeName"/>
              </a>

            </li>
          </xsl:for-each>
        </ul>

I've empty list...

It's not possible unpublish node because, after, I can not publish children.

I try this

<xsl:for-each select="$currentPage/Home/*[@isDoc]">
        <p><xsl:value-of select="@nodeName" /></p>
</xsl:for-each>

and I've tested that I'm in node "it" with <xsl:value-of select="$currentPage/@nodeName"/> ,but "for-each" ( see up ) return empty value..

This work...Thanks

<xsl:for-each select="$currentPage/*[@nodeName = 'Home']/*[@isDoc]">

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