Hey,

using the old syntax this should work to find out if the current page in a loop (current()) is a parent of the $currentPage:

<xsl:if test="current()/descendant-or-self::node[@id = $currentPage/@id]">

</xsl:if>

This will look if one of the descendants of the current node in the (omitted) xsl:for-each statement or the node itself has the same id as the id of the $currentPage. You can then set the class if the xsl:if is true.

Hope that helps,

Sascha

@Sascha: You shouldn't need to start an XPath with current() - that's always the starting point. (Likewise with the oft-seen "./")

/Chriztian

Thanks Chriztian, I remember having run into some trouble and that adding current() fixed it, but it is most probably that the error was actually something else and I just got used to writing it explicitly each time (9 characters!). Anyway, glad that you posted your answer and cleared that up, I'll try to get rid of the habit. :)

BTW: you've got one of my votes for MVP as I'm very grateful that you're sharing your Xsl wisdom with all of us! Greatly appreciated and I can say that I've learned a lot by reading your posts. :D

Cheers,

Sascha

Thanks for the responses.

Srdjan, you put me on the right track by using the ancestor axes selector to get the parents. i was thinking about it backwards.  I was able to test for the top level item and set the class if it matched.

is @isDoc part of the new schema as I was not able to get that to work, and it is not an attribute I can see in the umbraco xml cache?

Hi Dallas

You are welcome. I'm not sure if @isDoc is only in new schema, I havent been using the old schema that much in umbraco. But it is just a bool return if the node is document. If you are using the new schema you be able to see it if you output your $currentPage  <xsl:value-of select="$currentPage" />  and yes it is an attribute. all attributes start with @ so that way you can easy see what it is. 

is working on a reply...