Hi There,

I'm wanting to show all of the nodes that have the property showAsQuickLink. So far I can get the nodes I need at the root or homepage level, however as soon as I get into the other pages it soes not return anything.

Can someone please help me out with the syntax please?

Thanks in advance.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
  <!ENTITY nbsp "&#x00A0;">
]>
<xsl:stylesheet
 version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:msxml="urn:schemas-microsoft-com:xslt"
 xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets"
 exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets ">

  <xsl:output method="xml" omit-xml-declaration="yes"/>

  <xsl:param name="currentPage"/>
   <xsl:variable name="parent" select="$currentPage/*" />   
  <xsl:template match="/">
    <xsl:variable name="maxLevel" select="4"/>
    <ul>
      <xsl:for-each select="$parent/* [@isDoc and string(showAsQuickLink) = '1']">
        <li>
          <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:value-of select="@nodeName"/>
          </a>
        </li>
      </xsl:for-each>
    </ul>
  </xsl:template>
</xsl:stylesheet>