Hi Max

As I don't know your structure of your content, I'll just show you how you can grab all nodes of the type "Employee" in the entire tree.

Try this:

<xsl:variable name="root" select="$currentPage/ancestor-or-self::root" />
<xsl:for-each select="$root//Employee">
   <xsl:value-of select="@nodeName" /><br/>
</xsl:if>

The above code will create a list of all the nodes with a document type of Employee. It's not at all the most beautiful solution, but if you could show us your content structure we could maybe make a little more effective code.

But you can place the above code on any of your pages to show the list of Emplayee's. I hope it makes sense :)

/Kim A

i solved it using this

<xsl:for-each select="$currentPage/ancestor-or-self::root//* [name() = $documentTypeAlias and string(umbracoNaviHide) = '1'] ">

</xsl:for-each>

 u can use =1 in case ur hiding a page usign UmbraconaviHide

Thanks Guys

<xsl:variable name="documentTypeAlias" select="string('EmployeeRecords')"/>

Hi Max

Yeah that makes perfectly sense to me. You can change the code a bit, to make it shorter and delete the documentTypeAlias variable like this:

<xsl:for-each select="$currentPage/ancestor-or-self::root//EmployeeRecords[string(umbracoNaviHide) = '1'] ">

/Kim A

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