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At the moment im trying to get the parent name and the link to the parent page.My current code is like this
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::node/@id)" /> <a href="{parentPageUrl}"> <xsl:value-of select="$currentPage/parent::node/@nodeName" /> </a>
But sadly it dosnt work.Anyone got a solution.Thanks in advance
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*/@id)" /> <a href="{parentPageUrl}"> <xsl:value-of select="$currentPage/parent::*/@nodeName" /> </a>
the parent node will be obviously the doc type so check only through the doc-type not all the properties
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" /> <a href="{$parentPageUrl}"> <xsl:value-of select="$currentPage/parent::*[@isDoc]/@nodeName" /> </a>
Thanks, the parent page is now listet but it links to the subpage im currently on, using
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*/@id)" />
while
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" />
gives me an error
Maybe the error is elsewhere
<xsl:output method="html" omit-xml-declaration="yes" /><xsl:param name="currentPage"/><xsl:variable name="level" select="3"/><xsl:template match="/"><ul> <li style="margin:0 0 5px 0;"> <xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" /> <xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*/@id)" /> <a href="{parentPageUrl}"> <xsl:value-of select="$currentPage/parent::*/@nodeName" /> a> li><xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']"> <li style="margin:0 0 5px 0;"> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> a> li>xsl:for-each>ul>xsl:template>xsl:stylesheet>
<xsl:output method="html" omit-xml-declaration="yes" /><xsl:param name="currentPage"/><!-- Input the documenttype you want here --><xsl:variable name="level" select="3"/><xsl:template match="/"><!-- The fun starts here --><ul> <li style="margin:0 0 5px 0;"> <xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" /> <a href="{$parentPageUrl}"> <xsl:value-of select="$currentPage/parent::*[@isDoc]/@nodeName" /> </a> </li><xsl:for-each select="$currentPage/ancestor-or-self::*[@isDoc and @level = $level]/*[@isDoc and string(umbracoNaviHide) != '1']"> <li style="margin:0 0 5px 0;"> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> </li></xsl:for-each></ul></xsl:template></xsl:stylesheet>
Now everything works.Thanks Jedi masters
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Get parent name and url
At the moment im trying to get the parent name and the link to the parent page.
My current code is like this
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::node/@id)" /><a href="{parentPageUrl}">
<xsl:value-of select="$currentPage/parent::node/@nodeName" />
</a>
But sadly it dosnt work.
Anyone got a solution.
Thanks in advance
the parent node will be obviously the doc type so check only through the doc-type not all the properties
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" /> <a href="{$parentPageUrl}"> <xsl:value-of select="$currentPage/parent::*[@isDoc]/@nodeName" /> </a>Thanks, the parent page is now listet but it links to the subpage im currently on, using
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*/@id)" />while
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" />gives me an error
Maybe the error is elsewhere
<xsl:output method="html" omit-xml-declaration="yes" />
<xsl:param name="currentPage"/>
<xsl:variable name="level" select="3"/>
<xsl:template match="/">
<ul>
<li style="margin:0 0 5px 0;">
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" />
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*/@id)" />
<a href="{parentPageUrl}">
<xsl:value-of select="$currentPage/parent::*/@nodeName" />
a>
li>
<xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']">
<li style="margin:0 0 5px 0;">
<a href="{umbraco.library:NiceUrl(@id)}">
<xsl:value-of select="@nodeName"/>
a>
li>
xsl:for-each>
ul>
xsl:template>
xsl:stylesheet>
<xsl:output method="html" omit-xml-declaration="yes" />
<xsl:param name="currentPage"/>
<!-- Input the documenttype you want here -->
<xsl:variable name="level" select="3"/>
<xsl:template match="/">
<!-- The fun starts here -->
<ul>
<li style="margin:0 0 5px 0;">
<xsl:variable name="parentPageUrl" select="umbraco.library:NiceUrl($currentPage/parent::*[@isDoc]/@id)" />
<a href="{$parentPageUrl}">
<xsl:value-of select="$currentPage/parent::*[@isDoc]/@nodeName" />
</a>
</li>
<xsl:for-each select="$currentPage/ancestor-or-self::*[@isDoc and @level = $level]/*[@isDoc and string(umbracoNaviHide) != '1']">
<li style="margin:0 0 5px 0;">
<a href="{umbraco.library:NiceUrl(@id)}">
<xsl:value-of select="@nodeName"/>
</a>
</li>
</xsl:for-each>
</ul>
</xsl:template>
</xsl:stylesheet>
Now everything works.
Thanks Jedi masters
is working on a reply...
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You can continue this topic on the new forum by tapping the "Continue discussion" link below.