check whether node is published in xslt

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trfletch 595 posts 571 karma points

Jul 20, 2011 @ 11:22

Check whether node is published in XSLT

Hi all,

I have an Umbraco 4.7 website and I have created the following XSLT to list out some "featured" nodes, I am selecting the "featured" nodes using "uComponents:Xpath checkbox list" which only allows you to select published nodes. This is all works great apart from when a user unpublishes or deletes one the nodes that has been selected as "featured" which causes my XSLT to throw an error. I assume I need to add in some type of IF statement or something into the for:each that checks for only published nodes but I do not know how to do this. Can someone please help? My XSLT so far is:

<ul>
 
 <xsl:for-each select="umbraco.library:GetXmlNodeById(1076)/featuredProperties/XPathCheckBoxList/nodeId">
    <xsl:sort select="randomTools:GetRandom(0,count(umbraco.library:GetXmlNodeById(1076)/featuredProperties/XPathCheckBoxList/nodeId))" order="descending" />
 <xsl:variable name="node" select="umbraco.library:GetXmlNodeById(.)" />
  <xsl:variable name="mediaId" select="number($node/homepageImage)" />

    <li>
 
      <div class="featuredProperty">

        <div class="image">
          <xsl:if test="$mediaId &gt; 0">
            <xsl:variable name="mediaNode" select="umbraco.library:GetMedia($mediaId, 0)" />

            <img>
              <xsl:attribute name="src">
                <xsl:value-of select="$mediaNode/umbracoFile"/>
              </xsl:attribute>
              <xsl:attribute name="alt">
              </xsl:attribute>
            </img>
          </xsl:if>
        </div>
      
        <div class="heading">
        <xsl:value-of select="$node/heading"/>
        </div>
        <div class="price">
          £<xsl:value-of select="$node/price"/>pcm
        </div>
        <div class="description">
          <xsl:value-of select="$node/briefDescription"/>
        </div>
        <div class="line">
          <xsl:comment><!-- --></xsl:comment>
        </div>
        <div class="link">
          <a href="{umbraco.library:NiceUrl($node/@id)}">find out more</a>
        </div>
 
      </div>
    </li>

  </xsl:for-each >

  </ul>

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Jan Skovgaard 11258 posts 23500 karma points MVP 7x admin c-trib

Jul 20, 2011 @ 13:02

1

Hi Trevor

I think you should look into something like selecting the nodes where the @nodeName attribute is in fact not empty for instance

Like this <xsl:variable name="mediaId" select="number($node/homepageImage[@nodeName !=''])" />

I'm a bit unsure here since I can't remember what the XML looks like for media in 4.7 as I write this, but it's something like that you need to look into.

If you want further help on this, then please post a dump of the xml you get returned from the $mediaid variable :-)

/Jan

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trfletch 595 posts 571 karma points

Jul 20, 2011 @ 14:47
0
Hi Jan,

Thanks for the response, from what you suggested I managed to come up with the following IF statement which appears to resolve my issue:
```
<xsl:if test="$node/@nodeName !=''">
```
So my full XSLT is now:

<ul>

<xsl:for-each select="umbraco.library:GetXmlNodeById(1076)/featuredProperties/XPathCheckBoxList/nodeId">
    <xsl:sort select="randomTools:GetRandom(0,count(umbraco.library:GetXmlNodeById(1076)/featuredProperties/XPathCheckBoxList/nodeId))" order="descending" />
<xsl:variable name="node" select="umbraco.library:GetXmlNodeById(.)" />
<xsl:variable name="mediaId" select="number($node/homepageImage)" />

<xsl:if test="$node/@nodeName !=''">

    <li>

      <div class="featuredProperty">

        <div class="image">
          <xsl:if test="$mediaId > 0">
            <xsl:variable name="mediaNode" select="umbraco.library:GetMedia($mediaId, 0)" />

            <img>
              <xsl:attribute name="src">
                <xsl:value-of select="$mediaNode/umbracoFile"/>
              </xsl:attribute>
              <xsl:attribute name="alt">
              </xsl:attribute>
            </img>
          </xsl:if>
        </div>

        <div class="heading">
        <xsl:variable name="bedrooms" select="$node/bedrooms" />
        <xsl:variable name="propertyType" select="$node/propertyType" />
        <xsl:value-of select="umbraco.library:GetXmlNodeById($bedrooms)/@nodeName"/> bedroom <xsl:value-of select="umbraco.library:GetXmlNodeById($propertyType)/@nodeName"/>
        </div>
        <div class="price">
          £<xsl:value-of select="$node/price"/>pcm
        </div>
        <div class="description">
          <xsl:value-of select="$node/briefDescription"/>
        </div>
        <div class="line">
          <xsl:comment></xsl:comment>
        </div>
        <div class="link">
          <a href="{umbraco.library:NiceUrl($node/@id)}">find out more</a>
        </div>

      </div>
    </li>
</xsl:if>

</xsl:for-each >

</ul>
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