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Hi all,
I’ve been trying to get this to work for a while now.
I want to print out my navigation in two columns if the count of items exceeds 7. Creating a new div-class "megadropcol".
So far I got this to work – it prints out all items in just one column:
<!-- Drop Down Menu -->
<xsl:if test="count(./* [@isDoc and string(umbracoNaviHide) != '1']) > 0">
<div class="megadrop" style="display: none;">
<div class="megadropContent">
<div class="megadropcol">
<h3>Megadropheadline1</h3>
<ul>
<xsl:for-each select="./* [@isDoc and string(umbracoNaviHide) != '1']">
<li>
<xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
<xsl:attribute name="class">current</xsl:attribute>
</xsl:if>
<a href="{umbraco.library:NiceUrl(@id)}">
<xsl:value-of select="@nodeName"/>
</a>
</li>
</xsl:for-each>
</ul>
</div>
<!-- End of Drop Down Menu -->
I’m new to XSLT so bear with me J
Thanks in advance.
you could use something like <xsl:if test="position() < 7 "> to restrict the number of <li> items rendered out.
I've tried that one but no luck:
<!-- Drop Down Menu --> <xsl:if test="count(./* [@isDoc and string(umbracoNaviHide) != '1']) > 0"> <div class="megadrop" style="display: none;"> <div class="megadropContent"> <!--Start less than 7--> <xsl:if test="position() <= 7 "> <div class="megadropcol"> <h3>Megadropheadline1</h3> <ul> <xsl:for-each select="./* [@isDoc and string(umbracoNaviHide) != '1']"> <li> <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id"> <xsl:attribute name="class">current</xsl:attribute> </xsl:if> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> </li> </xsl:for-each> </ul> </div> </xsl:if> <!--End less than 7--> <!--Start greater than 7--> <xsl:if test="position() > 7 "> <div class="megadropcol"> <h3>Megadropheadline1</h3> <ul> <xsl:for-each select="./* [@isDoc and string(umbracoNaviHide) != '1']"> <li> <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id"> <xsl:attribute name="class">current</xsl:attribute> </xsl:if> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> </li> </xsl:for-each> </ul> </div> </xsl:if> <!--End greater that 7--> </div> </div> </xsl:if> </li> <!-- End of Drop Down Menu -->
The reason that's not working is because you're putting the line
<xsl:if test="position() <=7> outside the <xsl:for-each loop/>
the position() function only works inside the for-each loop
Thank you :-) That worked.
If anyone want the solution:
<!--Start less than 7--> <div class="megadropcol"> <h3>Megadropheadline1</h3> <ul> <xsl:for-each select="./* [@isDoc and string(umbracoNaviHide) != '1']"> <xsl:if test="position() <= 7 "> <li> <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id"> <xsl:attribute name="class">current</xsl:attribute> </xsl:if> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> </li> </xsl:if> </xsl:for-each> </ul> </div> <!--End less than 7--> <!--Start greater than 7--> <div class="megadropcol"> <h3>Megadropheadline1</h3> <ul> <xsl:for-each select="./* [@isDoc and string(umbracoNaviHide) != '1']"> <xsl:if test="position() >= 7 "> <li> <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id"> <xsl:attribute name="class">current</xsl:attribute> </xsl:if> <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a> </li> </xsl:if> </xsl:for-each> </ul> </div> <!--End greater than 7-->
No worries.
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Use two columns if items exceeds 7
Hi all,
I’ve been trying to get this to work for a while now.
I want to print out my navigation in two columns if the count of items exceeds 7. Creating a new div-class "megadropcol".
So far I got this to work – it prints out all items in just one column:
I’m new to XSLT so bear with me J
Thanks in advance.
you could use something like <xsl:if test="position() < 7 "> to restrict the number of <li> items rendered out.
I've tried that one but no luck:
The reason that's not working is because you're putting the line
<xsl:if test="position() <=7> outside the <xsl:for-each loop/>
the position() function only works inside the for-each loop
Thank you :-) That worked.
If anyone want the solution:
No worries.
is working on a reply...
This forum is in read-only mode while we transition to the new forum.
You can continue this topic on the new forum by tapping the "Continue discussion" link below.