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  • Dinesh 13 posts 33 karma points
    Sep 19, 2011 @ 22:28
    Dinesh
    0

    Getting value of External Link

    Hi,

    I have a property with alias name externalLink. I just want to get it's value in href of anchor tag when its present. This is what I have got so far. But it never gives me the value of externalLink even if it's present.

    <xsl:template match="/">

    <xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']">
      <div class="Nav2">
        <a href="{umbraco.library:NiceUrl(@id)}"> 
          <xsl:if test="data[@alias='externalLink']!= ''">
            <xsl:attribute name="href">
              <xsl:value-of select="data[@alias='externalLink']"/>
            </xsl:attribute>   
          </xsl:if>
          <xsl:value-of select="navTitle"/>
        </a>
      </div>
    </xsl:for-each>

    </xsl:template>

     

    Any help will be appreciated.

    Thanks

    D

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  • Tom Fulton 2030 posts 4996 karma points c-trib
    Sep 19, 2011 @ 22:38
    Tom Fulton
    1

    Hi,

    It looks like you are mixing the new and old schemas.  Try replacing "data [@alias='externalLink']" with just "externalLink", ie:

          <xsl:if test="externalLink!= ''">
            <xsl:attribute name="href">
              <xsl:value-of select="externalLink"/>
            </xsl:attribute>   
          </xsl:if>

    For more info:  our.umbraco.org/wiki/reference/xslt/45-xml-schema

    -Tom

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  • Chriztian Steinmeier 2726 posts 8320 karma points MVP 4x admin c-trib
    Sep 19, 2011 @ 22:39
    Chriztian Steinmeier
    1

    Hi Dinesh,

    You're actually doing it right, but the snippet you grabbed for the attribute thing uses the old XML schema (search for it if you want to know about it) - here's how that sample would look:

    <div class="Nav2">
    <a href="{umbraco.library:NiceUrl(@id)}">
        <xsl:if test="normalize-space(externalLink)">
            <xsl:attribute name="href">
                <xsl:value-of select="externalLink"/>
            </xsl:attribute>   
        </xsl:if>
        <xsl:value-of select="navTitle"/>
    </a>
</div>

    I, however, prefer a slightly different approach, using a match template:

    <xsl:template match="/">
...
    <div class="Nav2">
        <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:apply-templates select="externalLink[normalize-space()]" />
            <xsl:value-of select="navTitle"/>
        </a>
    </div>
...
</xsl:template>


<xsl:template match="externalLink">
    <xsl:attribute name="href">
        <xsl:value-of select="."/>
    </xsl:attribute>
</xsl:template>

    /Chriztian

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  • Chriztian Steinmeier 2726 posts 8320 karma points MVP 4x admin c-trib
    Sep 19, 2011 @ 22:40
    Chriztian Steinmeier
    0

    Snappy, Tom! :-)

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  • Dinesh 13 posts 33 karma points
    Sep 20, 2011 @ 17:00
    Dinesh
    0

    Tom & Chriztian,

    Thanks a lot guys. I am just catching up with XSLT. It works like a charm with your suggestions.

    -Dinesh

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