Hi Umbraco

This is not a casual cry forhelp - I've been stuck for 3 weeks on this apparantly simple issue:

On my homepage I want to list the last 5 child 'news items I have created, regardless of parentage - in date order (recent first)

My structure is:

Home

 - News

   *New item 1

   *New item 2

   *New item 3

- Guff

 *Guff item 1

 *Guff Item 2

etc

I want to list all the sub items in reverse date order, most recent first, regardless of parentage.

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">
  
  <xsl:output method="xml" indent="yes"/>
  <xsl:param name="currentPage"/>
  <xsl:variable name="level" select="1"/>
    <xsl:template match="/">


      <xsl:for-each select="$currentPage/*">
              <xsl:for-each select="./child::*">
              <xsl:sort select="@createDate" order="descending"/>
                <xsl:if test="@level=3">
                  <xsl:value-of select ="@nodeName"/>
                  <br></br>
                  <xsl:comment><xsl:value-of select ="content" disable-output-escaping="yes"/></xsl:comment>
                  <br></br>
                </xsl:if>
              </xsl:for-each>
      </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

This is my best shot so far.  It lists the level 3 items, but only in date order per node, rather that date order full stop.  I.e my list could be:

Guff item1

News item 1

News Item 2

Guff Item 2

etc,,,

Surely somone has done ths before!!!!  I'm close to giving up.

Adam