Hello - I've got a problem with content picker and I'm sure I have made mistakes in the xslt.

I have created an xslt file in order to render the content (nodeName and summary) of a selected source. In order to display this information on other templates in my website. The xslt I've created seems to only display a selected source's children (nodeName and summary) - rather than it's own.

Could someone let me know the changes I need to make. Here's my code:

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>
<xsl:variable name="source" select="/macro/source"/>
<xsl:variable name="maxItems" select="/macro/maxItems"/>

    <xsl:template match="/">

<ul>

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/* [@isDoc and string(umbracoNaviHide) != '1']">
  
<xsl:sort select="@createDate" order="ascending" />
<xsl:if test="position() &lt;= $maxItems">
  
   <li>
    <h2><a href="{umbraco.library:NiceUrl(@id)}">
      <xsl:value-of select="@nodeName"/>
      </a></h2>

    <p>
    <xsl:value-of select="summary"/>
    </p>
    
  </li>
  </xsl:if>
</xsl:for-each>
</ul>

</xsl:template>

Thank you!