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  • Cristian 24 posts 45 karma points
    Mar 02, 2012 @ 02:32
    Cristian
    0

    Get all id parent from currentPage

    Hi everybody

    there is a way to get all parent id Node from a certain node?

    for example

    node 1

      node2

      node3

         node4

    node5.....

    and i choose node4, but i need to know all id parents, node1-node2-node4

    there is a function in umbraco.library or some recursive templete to do this??

    regards.

     

     

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  • Markus Johansson 1701 posts 4879 karma points c-trib
    Mar 02, 2012 @ 07:32
    Markus Johansson
    0

    Are you talking about something lika a breadcrumb? I think that theres a build in template for that. But something like this:

     <xsl:for-each select="$currentPage/ancestor::* [@level &gt; $minCrumbLevel and string(umbracoNaviHide) != '1']">
           <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
             <xsl:value-of select="@nodeName"/>
           </a>
        </li>
     </xsl:for-each>

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  • Chriztian Steinmeier 2726 posts 8320 karma points MVP 4x admin c-trib
    Mar 02, 2012 @ 15:20
    Chriztian Steinmeier
    1

    Hi Cristian,

    If you just need the Ids for some reason, you can grab the @path attribute - it contains a "path of Ids" to the selected node, e.g.:

    If you have this setup:

Home (id:1050)
  Node1 (id:1052)
    Node2 (id:1053)
    Node3 (id:1054)
    Node4 (id:1055)

You can try:
<xsl:value-of select="$currentPage/@path" /> <!-- Will output: -1,1050,1052,1055 -->

     

    But you don't need the Ids if you just want to access the actual nodes - the ancestor-or-self:: axis will select them for you:

    <xsl:variable name="nodesInPathToCurrent" select="$currentPage/ancestor-or-self::*[@isDoc]" />

     

    /Chriztian

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  • Cristian 24 posts 45 karma points
    Mar 02, 2012 @ 15:39
    Cristian
    0

    Thanks for you reply! both of you.

    @path was the property that i was looking for!

     

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