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  • Fuji Kusaka 2203 posts 4220 karma points
    Apr 12, 2012 @ 10:13
    Fuji Kusaka
    0

    Display Only Child Nodes

    Am stuggling with this Xslt and cant figure a way out.

    Here is the situation and am trying to display only Child Nodes instead of Parent node by using GetXmlNodeById

    Folder Content (id= 1755 )
    Folder News 1
    News Item 1
    News Item 2
    Folder News 2 
    News Item 1
    News Item 2
    Folder News 3
    News Item 1
    News Item 2

    I only want to display the Child nodes of Folder News 1, Folder News 2 and Folder News 3.

     <xsl:for-each select="umbraco.library:GetXmlNodeById($level)//* [@isDoc]">
        <xsl:sort select="@createDate" order="descending" />
       <li>
        <xsl:value-of select="@nodeName"/>
        </li>
          <li> <xsl:call-template name="ImageGallery"/> </li> 
      </xsl:for-each>

    Instead am getting both the Folder and item Name. Any help on this please?

     

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  • Steffen Agger 13 posts 34 karma points
    Apr 12, 2012 @ 13:03
    Steffen Agger
    1

    xpath:

    "/" Selects children from the root node
    "//" Selects descendants from the root node

    So without any knowledge about xslt, i think you could do : umbraco.library:GetXmlNodeById($level)/*[@isDoc]

    also, you might wanna check these examples : http://our.umbraco.org/wiki/reference/xslt/45-xml-schema/xslt-examples-updated-to-new-schema

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  • Steffen Agger 13 posts 34 karma points
    Apr 12, 2012 @ 19:52
    Steffen Agger
    0

    wait... did you only want to show the items or the folders ? if items - it would be umbraco.library:GetXmlNodeById($level)/*[@isDoc]/*[@isDoc]

    *could/should be replaces by document types...

     

    i think... again not an xslt guy, but that xpath should match.

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  • Fuji Kusaka 2203 posts 4220 karma points
    Apr 12, 2012 @ 19:58
    Fuji Kusaka
    0

    Hi Steffen,

    I got this working what i did is 

    <xsl:for-each select="umbraco.library:GetXmlNodeById($level)//* [@isDoc][not(umbracoNaviHide = 1)]">
        <xsl:sort select="@createDate" order="descending" />   
          <xsl:call-template name="linkItems"/>
          <a href="{umbraco.library:NiceUrl(@id)}"><xsl:call-template name="ImageGallery"/> </a>
      </xsl:for-each>    
    </xsl:template>
        
        
          <!-- Template for the image -->
     <xsl:template name="ImageGallery">
       <xsl:variable name="mediapickerproperty" select="./galleryPicker"/>   
      <xsl:variable name="numMedia" select="4"/>         
           <xsl:if test="$mediapickerproperty &gt; 0">                
                      <xsl:for-each select="umbraco.library:GetMedia($mediapickerproperty, 1)/PhotoGallery[1]">
                         <xsl:if test="position() &lt;= $numMedia" >
                                   <img src="{umbraco.library:Replace(umbraco.library:GetMedia(@id, 0)/umbracoFile, '.', '_Thumbnail.')}"/>
                           </xsl:if>    
                  </xsl:for-each>            
        </xsl:if>   
    </xsl:template>
        <!-- Display only Nodes with Document Type "Album" -->
        <xsl:template name=" linkItems ">
          <xsl:if test="self::Album">
            <a href="{umbraco.library:NiceUrl(@id)}"> <xsl:value-of select="@nodeName"/> </a>
          </xsl:if>
        </xsl:template>

    So from my current page i get all the attributes from the Child Nodes then i just make a sorting to get the most current @createDate which will go through all Parents nodes checking for new documents created

    //fuji

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