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I need to copy the input XML file and place in output as a string.
I need to build a new output XML file.One of the new nodes will be a string and it needs to contain the complete input XML file.
Do not know how to do that
You might be looking for this:
<xsl:copy-of select="$currentPage" />
or for everything perhaps this
<xsl:copy-of select="umbraco.library:GetXmlAll()" />
For more information in general about the XML format used within Umbraco you could check this link: http://our.umbraco.org/wiki/reference/files-and-folders/umbraco-xml-format
Roel and Dan are on the right track, but rather than pull in a new instance of XML (via the GetXmlAll method), you can reuse the $currentPage param.
<xsl:copy-of select="$currentPage/ancestor::root" />
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copy full xml to output as string
I need to copy the input XML file and place in output as a string.
I need to build a new output XML file.One of the new nodes will be a string and it needs to contain the complete input XML file.
Do not know how to do that
You might be looking for this:
or for everything perhaps this
For more information in general about the XML format used within Umbraco you could check this link: http://our.umbraco.org/wiki/reference/files-and-folders/umbraco-xml-format
Roel and Dan are on the right track, but rather than pull in a new instance of XML (via the GetXmlAll method), you can reuse the $currentPage param.
is working on a reply...
This forum is in read-only mode while we transition to the new forum.
You can continue this topic on the new forum by tapping the "Continue discussion" link below.