Hello,

I'm using a Umbraco data type menu to create some small menus. 

My issues is that i don't know how to get data from menu inside xslt.

In designer looks fine and i have 4 menu items. When i read them in xslt with <xsl:value-of select="$site/footerMenu1"/> i got ..."THE FOUNDATIONlink1_hereTHE BOARDlink2_hereNEWS#PRESS#"

What i want is to iterate somehow the Menu items to optain something like this:

<ul class="links">

<li><a href="link1_here">THE FOUNDATION</a></li>

<li><a href="#">THE BOARD</a></li>

<li><a href="#">NEWS</a></li>

<li><a href="#">PRESS</a></li>

</ul>

If anyone knows how to access that menu object from xxlt please let me know.

Thank you 

Mihai