Hi All

I have been searching the forum for two days on this issue please can someone help?  I have a field in my news document type called Article Date alias 'articleDate'  I have written an xslt using formatdatetime but it returns nothing. The xslt is below and this is a link to the page that I used the macro in.  I've tried a few variations i.e. taken current page out etc.  Oh yes I'm using version 4.11

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
  <!ENTITY nbsp "&#x00A0;">
]>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:umbraco.library="urn:umbraco.library" exclude-result-prefixes="umbraco.library">
  <xsl:output method="xml" omit-xml-declaration="yes"/>
  <xsl:param name="currentPage"/>
   
  <xsl:template match="/">

<!-- The fun starts here -->
<ul>
<xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']">
   <xsl:if test="position() &lt;= 4">
  <li class="news">
    <h2><a href="{umbraco.library:NiceUrl(@id)}">
      <xsl:value-of select="@nodeName"/>
        </a> | <xsl:value-of select="umbraco.library:FormatDateTime($currentPage/data [@alias='articleDate'], 'dd.MM.yy')"/>
   
</h2>
           <xsl:variable name="firstParagraph" select="umbraco.library:StripHtml(substring-before(bodyText, '&lt;/p'))"/>
                           
      <p><xsl:value-of select="$firstParagraph"/></p>
  </li>
   </xsl:if>
</xsl:for-each>
</ul>

</xsl:template>

</xsl:stylesheet>