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  • Mats Ulrik Krüger 5 posts 65 karma points
    Jan 17, 2013 @ 21:49
    Mats Ulrik Krüger
    0

    Display all subnode subnodes

    Hello guys

    I'm new to all this xslt stuff.

    I want to display nodes from my child pages children

    - News    <-- this is where i want the node to display

      - 2012

        - Hello world!      <-- this is this node i want to display

      -2011

    I found a code which does this but it also displays the 2012 node.

    http://our.umbraco.org/forum/developers/xslt/12777-List-all-pages-and-sub-pages-from-current-node

    Can you guys please help.

    Thanks

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  • Mats Ulrik Krüger 5 posts 65 karma points
    Jan 17, 2013 @ 22:32
    Mats Ulrik Krüger
    100

    Hello I figured out that i could use

    <xsl:for-each select="$currentPage/*/*">

    But thanks anyway

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  • Chriztian Steinmeier 2726 posts 8320 karma points MVP 4x admin c-trib
    Jan 18, 2013 @ 08:05
    Chriztian Steinmeier
    0

    Hi Mats,

    Just for future proofing, you may consider modifying that just a little bit:

    <xsl:for-each select="$currentPage/*[@isDoc]/*[@isDoc]">

    This will make sure only to traverse "document" nodes in the XML, and not properties as well.

    It may not be a problem now, but if you later add a datatype that stores XML (e.g., the Multi-Node Tree Picker) you will begin to see some weird results.

    Also, if you add anything using position() (like odd/even rows etc.) you'll most likely see some weird jumps in the numbers you get.

    Anyway - just a small heads-up — welcome to the forums, and if you keep solving your own questions, you'll soon be an Umbraco expert :-)

    /Chriztian 

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