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  • Dan 1250 posts 3747 karma points admin c-trib
    Jan 29, 2010 @ 14:51
    Dan
    0

    Stupidly basic xslt question

    Just as I think I'm getting the hang of xslt, being able to traverse nodes etc, I'm stuck with something mega mega basic.

    How do I output the current node name (I know I could do this with an umbraco field in the template but it's more complicated than that)?  I've done the following but it returns nothing:

    <xsl:variable name="pageNode" select="$currentPage/node"/>
    <h2>
        <xsl:value-of select="@nodeName"/>
    </h2>

    Please somebody put me out of my misery!

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  • Thomas Höhler 1237 posts 1709 karma points MVP
    Jan 29, 2010 @ 15:01
    Thomas Höhler
    0

    You are at the current node so it has to be:

    <xsl:value-of select="$currentPage/@nodeName" />

    hth, Thomas

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  • Dan 1250 posts 3747 karma points admin c-trib
    Jan 29, 2010 @ 15:02
    Dan
    0

    Bingo, thanks Thomas.

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  • Nik Wahlberg 639 posts 1237 karma points MVP
    Jan 29, 2010 @ 15:03
    Nik Wahlberg
    0

    You should be able to do

    <xsl:value-of select="$currentPage/@nodeName"/>

    HTH

    -- Nik

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  • Nik Wahlberg 639 posts 1237 karma points MVP
    Jan 29, 2010 @ 15:03
    Nik Wahlberg
    0

    way too late...:)

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  • Thomas Höhler 1237 posts 1709 karma points MVP
    Jan 29, 2010 @ 15:04
    Thomas Höhler
    0

    For documentation, take a look at the wiki:

    http://our.umbraco.org/wiki/reference/xslt

    or Dougs great posts:

    http://blog.percipientstudios.com/2009/4/11/anatomy-of-an-umbraco-xslt-file.aspx

    http://blog.percipientstudios.com/2009/5/5/your-first-umbraco-xslt-macro.aspx

    Cheers, Thomas

     

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