I've updated it to set the value of the select, but it returns nothing:

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node [string(data [@alias='umbracoNaviHide']) != '1']//data [@alias = 'AlbumProject'] [not(.=preceding::data [@alias = 'AlbumProject'])]">
        <li>
                <xsl:value-of select="current()/data [@alias = 'AlbumProject']"/>
        </li>
</xsl:for-each>

There's obviously something wrong with the first line here, in the way it's searching for the nodes.

Hi Dan, I think I would go for the key/id approach where you generate keys for identical values. Check out this page for more info - it's a bit hairy if you are not already familiar with keys and id's, but it is extremely powerful and fast

http://blackpoint.dk/umbraco-workbench.aspx?Snippet=/umbraco-workbench/xslt/grouping--distinct-values.aspx

>Tommy

Thanks Tommy, that's going to be a 'challenge' for my limited skills.  I'll certainly look into it though.  In the meantime, I can live without the 'distinct' part of the requirement, but even this doesn't return anything:

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node [string(data [@alias='umbracoNaviHide']) != '1']//data [@alias = 'AlbumProject']">
        <li>
                <xsl:value-of select="current()/data [@alias = 'AlbumProject']"/>
        </li>
</xsl:for-each>

Any ideas?

It's definitely something to do with this syntax:

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node//data [@alias = 'AlbumProject']">

How can I just select that specific data from the nodes?

Hi Dan, should be something like this:

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node [data [@alias = 'AlbumProject']]">

Oh, and if you need help with the grouping, let me know and I can try to get you something for that...that will probably be your best approach for distinct output...

Thanks,
Nik

Scratch my post.... here's what you are trying to do...

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node [string(data [@alias='umbracoNaviHide']) != '1']">
        <li>
                <xsl:value-of select="data [@alias = 'AlbumProject']"/>
        </li>
</xsl:for-each>

Sorry...

Thanks Nik.  It's looping through now (it outputs two list items and I know there are two album nodes, so that follows) but the values are empty, so it's just returning <li></li><li></li>.

Can you confirm that the child nodes of the 'source' node in fact have that property? Is AlbumProject an property of a documentType or a documentType itself?

Thanks,
Nik 

The child nodes of the source node contain a text field with the alias 'AlbumProject'.

My bad!  Typo.  Thanks Nik, that's sorted the initial thing out - now I just need to get to grips with making it distinct.

Thanks for this Tommy, I've now got the following:

<xsl:key name="mykey" match="node" use="data [@alias = 'AlbumProject']"/>

<xsl:template match="/">

<xsl:for-each select="umbraco.library:GetXmlNodeById($source)/node [string(data [@alias='umbracoNaviHide']) != '1'] [generate-id() = generate-id(key('mykey', data [@alias = 'AlbumProject'])[1])]">
  <option>
        <xsl:value-of select="data [@alias = 'AlbumProject']"/>
        </option>
</xsl:for-each>

</xsl:template>

But it's not outputting anything.  Can you see a reason this isn't working?

Hi Dan,

There is at least one scenario where the above wouldn't produce any output: If the first of every possible AlbumProject value is placed on a hidden node.

Could this be the case?

Then you'd need to either:

A: Include the umbracoNaviHide predicate in the key definition, like this:

<xsl:key name="mykey" match="node[not(data[@alias = 'umbracoNaviHide'] = 1)]" use="data[@alias = 'AlbumProject']"/>

or B: Exclude it from the select, and handle it inside the for-each statement instead:

<xsl:for-each select="$source/node[generate-id() = generate-id(key('mykey', data[@alias = 'AlbumProject'])[1])]">
    <xsl:if test="not(data[@alias = 'umbracoNaviHide'] = 1)">
        <li>
            <xsl:value-of select="data[@alias = 'AlbumProject']"/>
        </li>
    </xsl:if>
</xsl:for-each>

Hi Dan, do you get any output if you remove the generate-id clause

[generate-id() = generate-id(key('mykey', data [@alias = 'AlbumProject'])[1])]

?

>Tommy

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