I'm stil a newbie at Umbraco and XSLT so please forgive me if this is a dumb question. I'm using the following code in my xslt to create a sitemap:

<xsl:variable name="maxLevelForSitemap" select="4"/>
<xsl:variable name="startLevel" select="2"/>

<xsl:template match="/">
    <div id="sitemap"> 
        <xsl:call-template name="drawNodes">  
            <xsl:with-param name="parent" select="$currentPage/ancestor-or-self::node [@level=1]"/>  
        </xsl:call-template>
    </div>
</xsl:template>

<xsl:template name="drawNodes">
    <xsl:param name="parent"/> 
        <xsl:if test="umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1 and umbraco.library:IsLoggedOn() = 1)">
            <ul>
            <xsl:for-each select="$parent/node [string(./data [@alias='umbracoNaviHide']) != '1' and @level &lt;= $maxLevelForSitemap]">                              
            <li>
                    <xsl:if test="current()/@level > $startLevel ">                                                
                            <a href="{umbraco.library:NiceUrl(@id)}">
                                <xsl:value-of select="@nodeName"/>
                            </a>                                                  
                    </xsl:if>
                    <xsl:if test="count(./node [string(./data [@alias='umbracoNaviHide']) != '1'
                                and @level &lt;= $maxLevelForSitemap]) &gt; 0   ">   
                        <xsl:call-template name="drawNodes">    
                            <xsl:with-param name="parent" select="."/>    
                        </xsl:call-template>  
                    </xsl:if>
            </li>
                </xsl:for-each>
            </ul>
        </xsl:if>
</xsl:template>

The problem I have now is that the li is also shown for the root item which i obviously don't want.

I tried to correct this by putting the <li> tag inside the if that tests the current level. but then I get the error that the <li> doesn't have a closing tag (quite normal of course). so I decided to put the <li>, </li> and the following if that tests for children inside the if that tests the level.

like this:

<xsl:if test="current()/@level > $startLevel ">       
    <li>                                      
        <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:value-of select="@nodeName"/>
        </a>                                                  

        <xsl:if test="count(./node [string(./data [@alias='umbracoNaviHide']) != '1'
            and @level &lt;= $maxLevelForSitemap]) &gt; 0   ">   
            <xsl:call-template name="drawNodes">    
                <xsl:with-param name="parent" select="."/>    
            </xsl:call-template>  
        </xsl:if> 
    </li>
</xsl:if>

but this doesn't work, which is quite a mystery to me.

So I need a way to add logic around the <li> tag to decide wether or not to show it. which brings me back to the error I get when the closing </li> tag is not in the same if. I tried to show <li> like this &lt;li&gt; and this <![CDATA<li>]]>, which also did not result in the wanted result.

I hope I explained the problem correctly. any help would be greatly apreciated.