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  • Fuji Kusaka 2203 posts 4220 karma points
    Sep 03, 2013 @ 15:19
    Fuji Kusaka
    0

    Get Record Id on submission

    Anyone can point out what am i doing wrong here cos i can get the current Record Id on submission in a xslt transformed email to the admin.

    The Record Id of the form is not displayind here.

      <xsl:stylesheet
      version="1.0"
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
      xmlns:msxml="urn:schemas-microsoft-com:xslt"
      xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:umbraco.contour="urn:umbraco.contour" xmlns:ucomponents.dates="urn:ucomponents.dates" xmlns:ucomponents.media="urn:ucomponents.media" xmlns:ucomponents.nodes="urn:ucomponents.nodes"
      exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets umbraco.contour ucomponents.dates ucomponents.media ucomponents.nodes ">
        <xsl:output method="xml" omit-xml-declaration="yes"/><xsl:param name="records"/>
        <xsl:template match="/">
            <xsl:variable name="id" select="umbraco.library:RequestQueryString('recordid')" />
            <xsl:if test="$id != ''">
                <xsl:variable name="record" select="umbraco.contour:GetRecord($id)" />
            </xsl:if>
    </xsl:template>

    All other records fields are displaying though

      <xsl:for-each select="$records//fields/child::* [caption = 'Race / Course']//value">
                    Race / Course :  <span style="color:#8EA73D;">
                        <strong>
                            <xsl:value-of select="."/>
                        </strong>
                    </span><br/>                
                </xsl:for-each>
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  • Fuji Kusaka 2203 posts 4220 karma points
    Sep 03, 2013 @ 19:09
    Fuji Kusaka
    0

    Any suggestion on this ??

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  • Fuji Kusaka 2203 posts 4220 karma points
    Sep 04, 2013 @ 07:15
    Fuji Kusaka
    0

    Even when i hardcode the Id i still dont get anything.

     <xsl:param name="records"/>
        <xsl:template match="/">
     
            Nom / Last Name :  <span style="color:#8EA73D;">
                <strong>
                    <xsl:value-of select="$records//fields/child::* [caption = 'Nom / Last Name']//value"/>
                </strong>
            </span><br/>
            <xsl:for-each select="$records">
                Posted by :  <xsl:value-of select="umbraco.library:FormatDateTime(./created, 'dddd, MMMM dd, yyy hh:mm tt')" disable-output-escaping="yes"/>
                <xsl:value-of select="umbraco.contour:GetRecord('dffc7f1a-5480-4339-92e4-03cd8128195e')"/>
            </xsl:for-each>

            

        </xsl:template>
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  • Fuji Kusaka 2203 posts 4220 karma points
    Sep 04, 2013 @ 08:41
    Fuji Kusaka
    101

    Got it working, just for the record am using contour 3.0.12 here.

      <xsl:value-of select="$records/id"/>
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